Urea (ch₄n₂o) is a common fertilizer that can be synthesized by the reaction of ammonia (nh₃) with carbon dioxide as follows:
2nh₃(aq)+co₂(aq)→ch₄n₂o(aq)+h₂o(l)
in an industrial synthesis of urea, a chemist combines 145.1 kg of ammonia with 211.4 kg of carbon dioxide and obtains 174.9 kg of urea. determine the theoretical yield of urea express your answer using four significant figures.

The answer to your question is:  68.3%

Explanation:

Urea = ?

Theoretical yield

Ammonia 145.1 kg

Carbon dioxide = 211.4 kg

Urea = 174.9 kg

MW NH3 = 17kg

MW CO2 44 kg

MW Urea = 60 kg

                     2NH₃(aq)     +    CO₂(aq)    →     CH₄N₂O(aq)    +     H₂O(l)

                     34                        44 kg                 60kg

                    145.1                   211.4                   174.9

Limiting reactant = NH3

                   34kg of NH3 60 kg of Urea

                    145.1 kg         x

                 x = (145.1 x 60) / 34

                x = 256 kg of Urea

Percent yield = 174.9 / 256 x 100

                     = 68.3%

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.