How many grams of nacl do you need to prepare 200 ml of a 5m solution? the molecular weight of nacl is 58.4 g/mol. smol 0.2l-1mol nacl lib imol naclx 8.glol nacl mol 58.19 nac

58.4 grams of NaCl is needed to prepare 200 ml of a 5M solution.

HOW TO CALCULATE MASS:

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The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

             Molarity = (# of moles ) / volume

             # of moles = Molarity x volume

             # of moles = 5 x 0.2

             # of moles = 1

              58.4 g 1 mol

              x            1 mol

              x = (1 x 58.4) / 1

             x = 58.4 g of NaCl

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"