The vapor pressure of water is 1.00 atm at 373 k, and the enthalpy of vaporization is 40.68 kj mol! . estimate the vapor pressure at temperature 363 and 383 k respectively. ansl = 0.697 atm, ans2 = 1.41 atm

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate of the reaction, we use clausius claypron equation, which is:

where,

= vapor pressure at temperature

= vapor pressure at temperature

= Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1)

= initial temperature =363 K

= final temperature =373 K

Putting values in above equation, we get:

The vapor pressure at temperature 363 K is 0.6970 atm

2)

= initial temperature =373 K

= final temperature =383 K

Putting values in above equation, we get:

The vapor pressure at 383 K is 1.410 atm

the answer would be a