Example problem describe the preparation of 1.0x102 ml of 6.0 m hcl from a concentrated solution that has a specific gravity of 1.18 and is 37% (w/w) hcl (36.5 g/mol)

15.3 ml of water is to be added to 7.1 M solution.

Explanation:

The relationship between specific gravity and density of a substance is given as:

Specific gravity of = 1.18

Density of water =

Putting values in above equation we get:

Given : 37 g of HCl is present in 100 g of solution

Volume of concentrated HCl solution=

According to the dilution law,

where,

= molarity of stock solution = ?

= molarity of diluted solution= 6.0 M

= volume of stock solution = 84.7 ml

= volume of diluted solution =

Therefore, the concentration of stock solution is 7.1 M

Mass of

To prepare 7.1 M solution , we need to add 21.9 g of HCl to 84.7 ml of water.

To prepare of 6.0 M HCl from a concentrated solution , (100-84.7) = 15.3 ml of water is to be added to 7.1 M solution.

explanation:

0.07 g/cm³

1.37 g/cm³