Specific heat material copper aluminum gold pyrex specific heat (j/g °c) 0.385 0.902 0.129 0.75 material water ice olive oil air specific heat (1/g °c) 4.18 2.01 2.38 1.00 if the same amount of heat was applied to a vessel containing 100.0 g of water and 100.0 g of olive oil, which would get hotter? why? if you had a 1.0 kg pot made of each metal, which pot would allow you to heat water to boiling more quickly? why? how much heat would it take to raise the temperature of 100.0 g of water from 20.0°c to 100.0 °c? (ignore the pot)

Explanation:

Since,     q =

So, larger is the specific heat of a substance less will be the change in its temperature.

Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.

As a result, water present in gold will heat readily.

              q =

Therefore, calculate the amount of heat required by the water as follows.

                 q =

                    =

                    = 33440 J

or,                 = 33.44 kJ               (as 1 kJ = 1000 J)

Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from to .

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6