What is the molarity of .342 grams of adenosine 3'5' cyclic monophosphate (camp) in one lite

The molarity of solution is

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute (CAMP) = 0.0000000342 g

Molar mass of CAMP = 329.21 g/mol

Volume of solution = 1 L

Putting values in above equation, we get:

Hence, the molarity of solution is

h let me think

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.