Everything else being equal, write a general expression showing how the exchange current density for a reaction changes as a function of temperature [e. g., write an expression for j0 (t) at an arbitrary temperature t as a function of j0 (t0) at a reference temperature t0]. if a reaction has j0 = 10−8a∕cm2 at 300 k and j0 = 10−4a∕cm2 at 600 k, what is δg‡ for the reaction? assume that the preexponent portion of j0 is temperature independent.

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

explanation:

0.07 g/cm³

1.37 g/cm³

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied