Suppose you have a liquid solution containing two components, a and b. the boiling point of pure a is 46.0 c and the boiling point of pure b is 116.0 c. your solution has a mole fraction of component a equal to 0.69, and the solution behaves as an ideal solution. what is the boiling point of this solution? (choose the best answer - a, b,c, or d)

67.7 °C

Explanation:

Since this solution has 2 substances, but not in the same proportion, you need to consider the fraction molar of each one and the boling point, it will be expected a higher temperature than the lower boiling point and a lower boiling point of the highest boiling point.

46 °C  x 0.69 = 31.74 °C

116°C x 0.31 = 35.96 °C

You add both: 31.74 °C + 35.96°C = 67.7 °C

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the answer is na (sodium)