5. a compound with a formula of lead (pb) and sulfur (s) was determined using the method in this experiment. a sample of pb was weighed into a porcelain crucible and covered with finely powdered s. then the crucible was covered and heated to allow the pb and s to react. after additional heating, all the unreacted s was burned off. the crucible was then cooled, weighed, and finally showed the following data: mass of crucible and cover, 25.429 grams mass of crucible, cover, and pb, g 29.465 grams mass of crucible, cover, and compound formed, g 30.107 grams what is the mass of s that reacted?

The mass of S that reacted is 0.642g

Explanation:

In this case we have

⇒ mass of crucible and cover, 25.429g

⇒ mass of crucible, cover, and Pb, 29.465g

⇒ mass of crucible, cover and commass of crucible and coverpound formed, 30.107g

The mass of Pb reacted = mass of crucible, cover, and Pb - mass of crucible and cover = 29.465 - 25.429 = 4.036g

The mass of compound formed = mass of crucible, cover and commass of crucible and coverpound formed  - mass of crucible and cover = 30.107 - 25.429g = 4.678g

The mass of S reacted = Mass of compound formed - mass of Pb reacted = 4.678 -4.036 = 0.642g

The mass of S that reacted is 0.642g

the atomic mass is the bottom number on the element.

-steel jelly