An electron that is initially 52 cm away from a proton is displaced to another point. if the change in the electrical potential energy as a result of this movement is 2.4 × 10−28 j, what is the final distance between the electron and the proton? the coulomb constant is 8.98755 × 109 n · m2 /c 2 , the acceleration due to gravity is 9.8 m/s 2 and the fundamental charge is 1.602 × 10−19 c . answer in units of m.

Explanation:

The given data is as follows.

       Change in Potential Energy =

Formula for change in potential energy is as follows

       Change in Potential Energy =

Hence, the potential difference between the two points will be as follows.

               V =

                   = volt

Therefore, the potential due to two charge initially is as follows.

                     V =

                         = volt

Hence,     volt =

                                  r = 0.493 m = 49.3 cm    (as 1 m = 100 cm)

Thus, we can conclude that the final distance between the electron and proton is 49.3 cm.

im pretty sure its b