Determine how many grams of co2 are produced by burning 8.21 g of c4h10

25.872 g of carbon dioxide will produced.

Explanation:

Given data:

mass of butane (C4H10) = 8.21 g

mass of carbon dioxide = ?

Solution:

Chemical equation

C4H10 + O2 → CO + H2O

Balanced chemical equation

2C4H10 + 13O2 → 8CO + 10H2O

First of all we will calculate the moles of butane.

number of moles = mass/ molar mass

number of moles = 8.21 g/ 58 g/mol

number of moles = 0.147 mol

from balanced chemical equation we will compare the moles of C4H10 with CO2,

             C4H10     :    CO2

                2           :      8

              0.147       :      8/2×0.147 = 0.588 moles

now we will calculate the mass of carbon dioxide from moles,

 mass of CO2 = number of moles × molar mass of CO2

 mass of CO2 =  0.588 mol × 44 g/mol

mass of CO2 = 25.872 g

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when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.