Consider 1 kg of nh3 that was compressed from 2.5 bar and 30°c to 5.0 bar in a well-insulated compressor. determine the (a) final temperature in c and (b) the work required in kj.

Explanation:

(a)   The given data is as follows.

               mass = 1 kg = 1000 g        (as 1 kg = 1000 g)

          Molar mass of = 17 g/mol

            = 2.5 bar =    (as 1 bar = )

            = 5 bar =

          = 30 + 273 = 303 K

For adiabatic process,   = constant = k

              = 1.33 =        

               (as PV = nRT)

                 =

                = 0.352

Also,       w =

                  =

                  = -84318.2 J

As 1 kJ = 1000 J. So, -84318.2 J = -84.318 kJ

Hence, the work required in kJ is -84318.2 J.

(b)    It is known that for adiabatic system Q = 0,

                          = -w

                             dT =

                                  =

                                  = 895.93 K

We known that dT =

so,                   895.93 = 303 K -                            

                          = (895.93 - 303)K

                                     = 592.93 K

                                     = (592.93 - 273.15)^{o}C

                                     =

Hence, the final temperature is .

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.