An alloy with an average grain diameter of 35 μm has a yield strength of 163 mpa, and when it undergoes strain hardening, the grain diameter reduces to 17 μm with an increase in yield strength to 192 mpa. if the coarseness of the alloy desired for a particular application cannot exceed 12 μm, what will be the expected yield strength?

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

d = diameter

K =Constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

     ------------1

d= 17 μm ,yield strength = 192 MPa

          ------------2

From equation 1 and 2

K=394.53

By putting the values of K in equation 1

Now when d= 12 μm

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.