Compute the %ic of the interatomic bond for each of the following compounds: mgo, gap, csf cds, and feo.

For MgO = 68%

For GaP = 3.5%

For CsF = 92.15 %

For CdS = 17.6%

For FeO = 47.8%

Explanation:

The ionic compound is formed by the complete transfer of electron from one atom to another. The one atom thus carry the positive charge while the other which accept the electron became negative. like in case of NaCl . This have 100% ionic character.

In covalent bond, the bond is formed by the sharing of electron between two atoms. The one atom which greatly pull the electrons towards itself is became partial negative while the other became partial positive atom. In this way electronegativity difference is created. For example in MgO, Mg is partial positive and has 1.31 electronegativity while the electronegativity of oxygen is 3.44.

Percent ionic character:

Formula:

%ionic character = [1- e∧-(0.25)(x)²] × 100

X= XA - XB

XA = higher electronegativity

XB = lower electronegativity

For MgO:

X = 3.44 - 1.31

X = 2.13

now we will determine the %ionic character.

%ionic character = [1- e∧-(0.25)(x)²] × 100

%ionic character = [1- e∧-(0.25)(2.13)²] × 100

%ionic character = [1- e∧-(0.25)(4.54)] × 100

%ionic character = [1- e∧-(1.135)] × 100

%ionic character = [1- 0.32)] × 100

%ionic character = 0.68 × 100

%ionic character = 68 %

For GaP:

Ga = 1.81

P = 2.19

X = 2.19 - 1.81 = 0.38

now we will determine the %ionic character.

%ionic character = [1- e∧-(0.25)(x)²] × 100

%ionic character = [1- e∧-(0.25)( 0.38)²] × 100

%ionic character = [1- e∧-(0.25)(0.1444)] × 100

%ionic character = [1- e∧-(0.0361)] × 100

%ionic character = [1- 0.965)] × 100

%ionic character = 0.035 × 100

%ionic character = 3.5 %

For CsF:

Cs = 0.79

F=  3.98

X= 3.98- 0.79 = 3.19

now we will determine the %ionic character.

%ionic character = [1- e∧-(0.25)(x)²] × 100

%ionic character = [1- e∧-(0.25)( 3.19)²] × 100

%ionic character = [1- e∧-(0.25)(10.18)] × 100

%ionic character = [1- e∧-(2.545)] × 100

%ionic character = [1- 0.0785)] × 100

%ionic character = 0.9215 × 100

%ionic character = 92.15 %

For CdS:

Cd = 1.7

S = 2.58

X = 2.58 - 1.7 = 0.88

now we will determine the %ionic character.

%ionic character = [1- e∧-(0.25)(x)²] × 100

%ionic character = [1- e∧-(0.25)( 0.88)²] × 100

%ionic character = [1- e∧-(0.25)(0.774)] × 100

%ionic character = [1- e∧-(0.1936)] × 100

%ionic character = [1- 0.824)] × 100

%ionic character = 0.176 × 100

%ionic character = 17.6 %

For FeO:

Fe = 1.83

O = 3.44

X= 3.44 - 1.83 = 1.61

now we will determine the %ionic character.

%ionic character = [1- e∧-(0.25)(x)²] × 100

%ionic character = [1- e∧-(0.25)( 1.61)²] × 100

%ionic character = [1- e∧-(0.25)(2.6)] × 100

%ionic character = [1- e∧-(0.65)] × 100

%ionic character = [1- 0.522)] × 100

%ionic character = 0.478 × 100

%ionic character = 47.8 %

where is the following

explanation:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.