Estimate the density of a mixture of50% acetone and 50% water by volume additivity

892 grams/liter

Explanation:

in order to calcuñate this you jus have to add the percentage of the volume of both water has a density of 1000 gms/liter or 1 gram/mililter and the acetone is 784 g/l so if that is 50%-50% you multiply that by .5 and you add them up and get the density of the mix of them both:

1000*,5= 500g/l

784*,5=392 g/l

500+392=892g/l

So the density of a mixture 50-50 of water and acetone would be 892 g/l

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error