Calculate the enthalpy change for the reaction: caf2 + h2so4 → 2hf + caso4 given that enthalpy changes of formation of: ah [caf2] = -1220 kj mol-1. ah[h2so4] = -814 kụ mol-1. ah[hf] = -271 k] mol-1. ahf(caso4) = -1434 kj mol-1.

The enthalpy change of the reaction is 58 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as

The equation used to calculate enthalpy change is of a reaction is:  

For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Hence, the enthalpy change of the reaction is 58 kJ.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8