Which of the following is a correct set of quantum numbers for outermost valence electron in a neutral atom in the ground state of oxygen o 3,1,2 0 2,-1,1 0 3,0,0 0 2,1,-1

2,1,-1

Explanation:

The electronic configuration of oxygen is

The valence electrons are in the second principle quantum number, which means that the value of n = 2.

For, n =2,

l can be 0 or 1 which corresponds to s and p orbital respectively.

If l = 1 , which is p orbitals and it exits in 3 degenerate orbitals which has values of m = -1 , 0 , +1

So, The possible set pf quantum number for the outermost valence electron of the oxygen atom is 2, 1, -1.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

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