You need to determine the mass of an aqueous solution. you determine the mass of your 10.0 ml graduated cylinder to be 23.529 g. after adding a volume of 3.27 ml of solution to the cylinder, you reweigh it and determine the new mass to be 26.694 g. what is the mass of the aqueous solution? webassign will check your answer for the correct number of significant figures. g what is the density of the aqueous solution? webassign will check your answer for the correct number of significant figures. g/ml

The density of aqueous solution is 0.968 g/mL

Explanation:

For calculating density we need to have the mass and the volume and apply the following equation:

Density = Mass (g) / volume (mL)

We have the volume of the solution, 3.27 mL. The mass come from subtracting 26.694 - 23.529 = 3.165 g

Applying Density equation:

Density = 3.165 g / 3.27 mL = 0.96788990825

The value has a higher quantity of significant figures is the mass, so, the result must be to have the same figures and approximate the result in the last digit to the next or to the previous number. In this case, the mass has 3 number of significant figures and the third significant number in the result must be 8 because the fourth number is major than 5. If it were less, the third significant number were 7.

I hope my answer helps you

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml