Chemistry, 20.09.2019 00:00 jgunt8277

Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)
a. oxygen and neon are in the same group and have the same number of valence electrons.
b. oxygen and sulfur are in the same period and have the same number of electron shells.
c. oxygen and neon are in the same period and have the same number of electron shells.
d. oxygen and sulfur have the same number of valence electrons.
e. oxygen and sulfur are most similar because they are in the same family and have similar chemical properties.
f. oxygen and neon have similar chemical properties.

Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)

Answers: 1

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Answers

Answer from: twistedhyperboles

from the way I understand the question I think the answer is (B)

Explanation:

Because the distribution into shells of oxygen is 2,6 and in sulfur is 2,8,6 and oxygen has a 8th number of electrons and sulfur has the 16th number of electrons

Answer from: Bgreene2377

Option C, option D and option E is correct

Explanation:

Atomic number of O = 8

Electronic configuration of O = 1s^22s^22p^4

No. of valence electron = 6

Atomic number of S = 16

Electronic configuration of O = 1s^22s^22p^63s^23p^4

No. of valence electron = 6

Atomic number of Ne = 10

Electronic configuration of Ne = 1s^22s^22p^6

No. of valence electron = 8

No. of electron shell present in any atom is equal to principle quantum no.

So, no. of electron shell in O = 2

no. of electron shell in S = 3

no. of electron shell in Ne = 2

O is present in period 2 and group 16.

S is present in period 3 and group 16.

Ne is present in period 2 and group 16.

So, O and S are present in same group. Elements of same group or family display similar chemical properties.

So, among correct options are:

option C: Oxygen and Neon are in the same period and have the same number of electron shells.

Option D: Oxygen and Sulfur have the same number of valence electrons.

Option E: Oxygen and Sulfur are most similar because they are in the same family and have similar chemical properties.

Answer from: Quest

i think it's c. i'm not sure but i think so.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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Which of the following is true about oxygen (o), sulfur (s) and neon (ne)? (choose 3)
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