Investigators are studying a protein that must be phosphorylated to be activated. which method could be used to separate the phosphorylated form of the protein from the form that lacks an activating phosphate group?

There is two common methods to separate a phosphorylated protein from the proteins who does not have the phosphate group.

1. Western Blot test

The Western blot test is a method where we separate of the biological sample with SDS- PAGE (electrophoresis method) and then we transfer to a nitrocellulose membrane. We use a phospho-specific antibody to identify the protein of interest.

2. The ELISA test

this test is also a powerful method for measuring protein phosphorylation. Elisa test is more are quantitative than Western blot test and also shows great advantage in studies related with kinase activity. In this test we use a capture antibody specific for the desired protein, independent of the phosphorylation state. The target protein is binded to the antibody-coated plate.  and finally a detection antibody specific for the phosphorylation site analyzed is added. In these test it is possible to use colorimetric or fluorometric detection.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.