More good buffers. one liter of a buffer is prepared consisting of 100 mm hepps at ph 8.0. what is the concentration of the protonated form of hepps in this solution?

The concentration of the protonated form of HEPPS -HHEPPS- is:

50mM

Explanation:

HEPPS is a buffering agent used in biology and biochemistry. The pKa of HEPPS is 8.00. To solve this problem it is necessary to use Henderson-Hasselbalch formula:

pH = pka + log

Replacing:

8,0 = 8,0 + log

1 = (1)

The concentration of the buffer is:

100mM = [HEPPS⁻] + [HHEPPS] (2)

Replacing (2) in (1) you will obtain:

[HHEPPS] = 50 mM

And:

[HEPPS⁻] = 50 mM.

Thus, the concentration of the protonated form of HEPPS -HHEPPS- is:

50mM

I hope it helps!

i think   the answer is c hope i'm right

hi my dude or dudette