Asolution contains one or more of the following ions: ag+, ca2+, and fe2+. when sodium chloride is added to the solution, no precipitate forms. when sodium sulfate is added to the solution, a white precipitate forms. then, the precipitate is filtered off and sodium carbonate is added to the remaining solution, and a precipitate forms. which of the ions were present in the original solution? select all that apply.

the ion present in the original solution is Ca2+

Explanation:

Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.

Step1 : If we add Nacl to the solution, there is no precipitate formed

⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present

Step2 : If we add Na2SO4 to the solution, a white precipitate is formed

The possible ions to bind at SO42- are Ca2+ and Fe2+

But the white precipitate formed, points in the direction of Ca2+

⇒This means calcium is present

Step3 : If we add Na2CO3 to the filtered solution, there is a precipate formed

Ca2+ will bind also with CO32- and form a precipitate

So the ion present in the original solution is Ca2+

i believe the answer is three water molecules