Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. no2- + 6e- -> nh4+ (-0.41 volts) o2 + 4e- -> 2h2o (+0.82 volts) using the information given, calculate the δe for this reaction, balance the full reaction to determine the n, the number of electrons transfered when 78 molecules of nh4+ are oxidized. finally, use the simplified nernst equation