a sample of bromine was analysed in a time of flight (tof) mass spectrometer and
found to contain two isotopes, 79br and 81br
after electron impact ionisation, all of the lons were accelerated to the same
kinetic energy (ke) and then travelled through a flight tube that was 0.950 m long.
the 79br+ lons took 6.69 x 10^-4 to travel through the flight tube.
calculate the mass, in kg, of one lon of 79br+
calculate the time taken for the 81br+ ions to travel through the same flight tube.
the avogadro constant, l = 6.022 x 10mol!
ke = 5 roy? where m = mass (kg) and v= speed (m 3-')
where d = distance (m) and t = time (s)
(5 marks)

idk what the question is about

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

answerambulatory;