Calculate the number of oxygen atoms in a 140,0 g sample of fron(iii) oxide (fe, 0).
be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.

7.951 x 0²³atoms

Explanation:

Mass of Fe₃O₄ = 140g

Solution:

To find the number of oxygen atoms in iron(III) oxide, we first find the number of moles in the compound:

  Number of moles =

   Molar mass of Fe₃O₄ = (3x56) + (4x64) = 168 + 256 =424g/mol

  Number of moles = = 0.33mole

 1 mole of an atom contains 6.02 x 10²³atoms

∴number of oxygen atoms in Fe₃O₄ = 4 x 0.33 x 6.02 x 10²³atoms

                                                           = 7.951 x 0²³atoms

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.

b) nuclear ive learned that in a pedtrodic table