If you have 16 g of manganese (ii) nitrate tetrahydrate, how much water is required to prepare 0.16 m solution from this amount of salt? ol 0 0.01 l the task is impossible, as manganese nitrate is insoluble in water o 0.10 l 398 ml

The volume of water required is 398 mL

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

Hence, the volume of water required is 398 mL