Question 5 (1 point) you need to prepare 1.0 l of solution containing 1.0 mm mgcl2 and 0.15 m nacl form stock solutions of 1.0 m mgcl2 and 0.50 m nacl. you will: use 1.0 ml mgcl2, 0.30 l nacl, fill up with water to 1 l ouse 100 ml mgcl2, 300 ml nacl, fill up with water to 1 l use 1.0 ml mgcl2, 30.0 ml nacl, fill up with water to 1 l use 0.0010 l mgcl2, 0.030 l nacl, fill up with water to 1 l use 100 ml mgcl2, 300 ml nacl, fill up with water to 1l

Use 1.0 mL MgCl2, 0.30 L NaCl, fill up with water to 1 L

Explanation:

The dilution equation relates the concentration C₁ and volume V₁ of an undiluted solution to the concentration C₂ and volume V₂ as follows:

C₁V₁ = C₂V₂

We want to solve for V₁, the amount of stock solution that is required for the dilution to 1.0L.

V₁ = (C₂V₂) / C₁

For the MgCl₂ stock solution, the following volume is required:

V₁ = (C₂V₂) / C₁ = (1.0mM)(1.0L) / (1.0M) = 1 mL

For the NaCl stock solution, the following volume is required:

V₁ = (C₂V₂) / C₁ = (0.15M)(1.0L) / (0.50M) = 0.30 L

The volumes V₁ are the diluted until the total volume reaches V₂.

elements make up everything, and they combine to make compounds.

the answer is c

give me abc and i will get it for u.