Calculate how many g of ammonia will be produced from 9.35 g of nitrogen gas and excess hydrogen using the following equation: 2 nh(g) 3 h2(g) n(g) 4 answer

The mass of ammonia produced in the reaction is 11.36 g

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of nitrogen gas = 9.35 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

The chemical reaction for the formation of ammonia from hydrogen and nitrogen follows:

As, hydrogen gas is present in excess. So, it is considered as an excess reagent.

Nitrogen gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of nitrogen gas is producing 2 moles of ammonia gas

So, 0.334 moles of nitrogen gas will produce = of ammonia gas.

Now, calculating the mass of ammonia gas by using equation 1, we get:

Moles of ammonia gas = 0.668 mol

Molar mass of ammonia gas = 17 g/mol

Putting values in equation 1, we get:

Hence, the mass of ammonia produced in the reaction is 11.36 g

since electrons are negative the answer is neagtaive