A1.24g sample of a hydrocarbon, when completely burned in an excess of o2 yields 4.04g co2 and 1.24g h20. draw plausible structure for the hydrocarbon molecule

Plausible structure has been given below

Explanation:

4.04 g of = = 0.0918 moles of

1 mol of contains 1 mol of C atom

So, 0.0918 moles of contains 0.0918 moles of C atom

1.24 g of = = 0.0689 moles of

1 mol of  contain 2 moles of H atom

So, 0.0689 moles of contain of or 0.138 moles of

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is

So, molecular formula of one of it's analog is

Plausible structure of has been given below.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o