Determine the theoretical yield of p2o5, when 3.07 g of p reacts with 6.09 g of oxygen in the following chemical equation
4 p + 5 o2 > 2 p2o5

14.2 grams

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

given mass of phosphorous (P) = 3.07 g

Molar mass of phosphorous (P) =  31 g/mol

Putting in the values we get:

given mass of oxygen = 6.09 g

Molar mass of oxygen =  32 g/mol

Putting in the values we get:

According to stoichiometry:

4 moles of phosphorous combine with 5 moles of oxygen

Thus 0.1 moles of phosphorous combine with = moles of oxygen

Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.

4 moles of phosphorous gives=  2 moles of

Thus 0.1 moles of phosphorous gives = moles of

mass of

Thus the theoretical yield of is 14.2 grams.

space exploration has led to the development and technological improvement of many everyday items. (if this answer is wrong i will find the right answer) : )