How many grams of calcium chloride would you need to make 1 l of solution containing 5 ppm calcium (ca)?

Explanation:

The given data is as follows.

           Volume = 1 L,    Concentration of Ca = 5 ppm or 5 mg/L

As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.

Hence, calculate molarity of calcium as follows.

           Molarity of Ca =

                                  =

         Molarity of Ca =

Hence, molarity of is . Since, volume is same so, moles of calcium chloride will be .

Thus, we can conclude that mass of will be as follows.

                    (molar mass of = 110.984 g/mol)

               = 0.0138 g

Thus, we can conclude that mass of is 0.0138 g.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.