Identify the isotope where a equals 49 and z equals 22.
a) indium-22
b) indium-27
c) indium-49
d) titanium-22
e) titanium-27
f) titanium-49
g) none of the choices are correct.

Titanium-49

Explanation:

A is the mass number and is equal to number of protons + number of neutrons.

Z is the atomic number and it is equal to number of protons and number of electrons.

Now the isotope will be recognized by the mass number which is 49 a.m.u. and the atomic number which is equal to 22. The isotope will be Titanium-49.

D) Titanium-22

Explanation:

Titanium is one of the transition metal elements. It is the 22nd element on the periodic table.

From the statement of the problem:

  A  is the mass number of the unknown atom which is 49. The mass number is the number of protons and neutrons in the nucleus of the atom.

   Z is the atomic number of the unknown atom which is 22. The atomic number is the number of protons in an atom. It is the same as the number of electrons for a neutral atom.

To identify the element, we simply use the atomic number because the periodic table of element is a function of the atomic number Therefore, the element with atomic number 22 on the periodic table is Titanium.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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