Ameasured sample of argon gas has a volume of 20.0l at a pressure of 660 mmhg. what is the final volume if the pressure is decreased to 550 mmhg?
17l
240l
5.5l
24l

The answer to your problem is: V2 = 24.0 L

Explanation:

To solve this problem we need to use the Boyle's law that says:

          P1V1 = P2V2

Data:

P1 = 660 mmHg

P2 = 550 mmHg

V1 = 20 l

V2 = ? l

Now, we need to clear V2 from the equation

         V2 = P1V1/P2

Substitution

         V2 = 660 mmHg x 20 l / 550 mmHg

         V2 = 13200 / 550

Result           V2 = 24.0 l

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

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