Astudent finds that 24.52 ml of 0.7170 m silver nitrate is needed to precipitate all of the bromide ion in a 50.00-ml sample of an unknown. what is the molarity of the bromide ion in the student's unknown?

The molarity of bromide ions is 0.348 M.

Explanation:

To calculate the moles of cadmium nitrate, we use the equation:

      .....(1)

Molarity of silver nitrate = 0.7170 M

Volume of silver nitrate = 24.52 mL = 0.02452 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

The chemical equation for the reaction of silver nitrate and bromide ions follows:

By Stoichiometry of the reaction:

1 mole of silver nitrate reacts with 1 mole of bromide ions.

So, 0.0174 moles of silver nitrate will react with = of bromide ions.

Now, calculating the molarity of bromide ions by using equation 1, we get:

Moles of bromide ions = 0.0174 moles

Volume of solution = 50 mL = 0.05 L

Putting values in equation 1, we get:

Hence, the molarity of bromide ions is 0.348 M.

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?