Saved propane burns in air according to the equation c3ha(g 502lg)3co2) + 4h20(g) what volume of o2 in liters would be required if 15.0 l of propane burns, assuming that all of the gases are under the same conditions? short answer toolbar navigation e i e b ius ea this question will be sent to your instructor for grading. 20 of 25 l next > prev nere to search

75 liters of in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Lat STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

According to stoichiometry:

1 mole of propane combines with = 5 moles of oxygen

Thus 0.67 moles of propane combine with  =

Volume of

Thus 75 liters of in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.