Calculate the mass of nitrogen dissolved at room temperature in an 99.0 l home aquarium. assume a total pressure of 1.0 atm and a mole fraction for nitrogen of 0.78. express your answer using two significant figures.

Explanation:

The given data is as follows.

          = 1 atm,         = 0.78

Now, we will calculate the partial pressure of given nitrogen gas as follows.

                        =

                        = 0.78 atm

According to the Henry's law we will calculate the solubility of nitrogen as follow.

                       =

                       =

Now, for 99.0 L the amount of nitrogen gas dissolved is calculated as follows.

        =

        = 1.32 g

Thus, we can conclude that the mass of nitrogen dissolved at room temperature in an 99.0 L home aquarium is 1.32 g.

i think   the answer is c hope i'm right

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