Heat transfer coefficient in evaporatora 10 wt% naoh solution is concentrated to 40 wt% in an evaporator operating at 40 kpa. the feed enters the evaporator at a mass flow rate of 4200 kg/hr and a temperature of 21.1°c. the evaporator area is 1.12 m2. saturated steam at 110°c is used for heating. a)calculate the boiling point rise (bpr) in the evaporator; b)calculate the steam flow rate in kg/hr; c)calculate the overall heat transfer coefficient in units of w/(m2*k).

no but i do not usually comment or use my voice that much when it comes to social media

a corroding iron, if that's one of your choices

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole