What is the mole fraction of acetic acid in a solution containing 2 moles of vinegar and 3 moles of water? a. 2 b. 3 c. 0.4 d. 0.5

C. 0.4.

Explanation:

∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).

- no. of moles of acetic acid = 2, no. of moles of water = 3.

- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.

∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (2)/(5) = 0.4.

Answer - The right answer for the given question is option c, 0.4

Explanation- As we know when a solution’s mole divides the solute’s mole the quotient (or the answer) we get is the mole fraction of substance.

Since in the question’s data solute, given as vinegar and the moles of vinegar are 2 and the data shows the solution is given as water and the moles of water is given as 3. Now we know mole fraction can be calculated by dividing the two. So by dividing we can get the result as 0.4.

the answer is 1 i believe

fe 55.85 g/mol and h2o 18.02 g/mol.