Glycine has two ionizable groups, a carboxyl group and an amino group. calculate the fraction of glycine that has its amino group protonated at ph 8.6. the pka values for glycine are pk1 = 2.34 (carboxyl group) and pk2 (amino group)= 9.60.

0.9

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

pH=pKa+log[base]/[acid]

Given that :

pH = 8.6

pK2 will be used for the amino group which is = 9.60

So,

8.60=9.60+log[base]/[acid]

log[base]/[acid]=1.0

[base]/[acid] = 10

So,

[base] = 10 [acid]

Fraction is:

[base] / ([base] + [acid]) = 10 [acid] / 10 ([acid] + [acid]) = 10 / 11 = 0.9

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

if you're asking what comes out, it's steam.