How many millilitres of water at 23 degree centigrade with the density of 1.00 g / ml must be mixed with 180 ml (about 6 oz) of coffee at 95 degree centigrade so that the resulting combination will have a temperature of 60 degree centigrade assume that coffee and water have the same density and the same specific heat

141.7475 milliliters of water must be added.

Explanation:

Heat gained by water will be equal to heat loss by the coffee solution.

Mass of water =

Specific heat capacity of water=

Initial temperature of the water=

Final temperature of water coffee solution= = 60 °C

Mass of coffee solution=

1 oz = 28.3495 grams

Specific heat capacity of coffee=

Initial temperature of the coffee solution=

Final temperature of water coffee solution= =T=60 °C

On substituting all values:

we get,

Density of the water = 1.00 g/mL

Volume of the water =

141.7475 milliliters of water must be added.

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the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.