Calculate the heat capacity, in joules and in calories per degree, of the following:
(a)45.8 g of nitrogen gas
(b)1.00 pound of aluminium metal

a) 47.632 J  , 11.384 cal/ °C

b) 406.87 J  , 97.246 cal / ˚C

Explanation:

Given;

a) 45.8 g of nitrogen gas

Heat capacity per degree = mass × Specific heat

the specific heat of Nitrogen gas = 1.04 J/g

thus,

The Heat capacity of 45.8g Nitrogen gas = 45.8 × 1.04  = 47.632 J

also,

1 calorie = 4.184 J

therefore,

Heat capacity in calories = 47.632 J × (1 cal / 4.184 J) = 11.384 cal/ °C

b) 1.00 pound of aluminium metal

We know, 1 pounds = 453.59237  grams

thus,

Heat capacity per degree = mass × Specific heat

Specific heat of the Aluminium = 0.897 J/g

therefore,

Heat capacity per degree = 453.6 × 0.897  = 406.87 J

and in calories per degree

Heat capacity = 406.87 × (1 cal / 4.184 J) = 97.246 cal / ˚C

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: