How many molecules of c2h4cl2 can be prepared from 15 c2h4 molecules and 8cl2 molecules?

8 molecules of C₂H₄Cl₂

Explanation:

Molecules of C₂H₄ = 15 molecule

Molecules of Cl₂ = 8 molecules

Molecules of C₂H₄Cl₂ =?

First of all we will write the balance chemical equation,

C₂H₄ + Cl₂ → C₂H₄Cl₂

we are given 8 molecules of Cl₂ and 15 molecules of  C₂H₄, which means that 8 molecules of chlorine react with 8 molecules of C₂H₄ and will limit the reaction product. The seven molecules of C₂H₄ will remain unreactive. So , the chlorine will be the limiting reactant.

8 molecules of Cl₂ × 1 mole of C₂H₄Cl₂/ 1 mole of Cl₂

8 molecules of C₂H₄Cl₂

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).