Chemistry, 02.09.2019 22:30 goosenar

Magnesium will burn in air to form both mg3n2 and mgo. what mass of each product would be found if burning a 3.26 g sample of magnesium to completion produces a combined total of 5.09 g of the two products

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Answer from: JayceMeyers06

The mass of MgO formed is 3.502 grams and mass of Mg_3N_2 formed is 1.587 grams.

Explanation:

We are given:

Total mass of magnesium reacted = 3.26 g

Total mass of products formed = 5.09 g

To calculate number of moles of a substance, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For calculating mass of MgO:

The chemical equation for the formation of magnesium oxide follows:

$2Mg+O_2\rightarrow 2MgO$

Let 'x' grams of magnesium is reacting to form magnesium oxide.

Molar mass of Magnesium = 24.3 g/mol

Putting values in equation 1, we get:

Number of moles of magnesium = $\frac{x}{24.3}mol$

By Stoichiometry of the reaction:

2 moles of magnesium produces 2 moles of MgO

So, $\frac{x}{24.3}$ moles of magnesium will produce $\frac{2}{2}\times \frac{x}{24.3}=\frac{x}{24.3}$ moles of MgO

Molar mass of MgO = 40.3 g/mol

Putting values in equation 1, we get:

Mass of MgO = $\frac{x}{24.3}\times 40.3=(1.66\times x)g$

Mass of magnesium oxide = $(1.66\times x)g$ = X grams

For calculating mass of Mg_3N_2

The chemical equation for the formation of magnesium nitride follows:

$3Mg+N_2\rightarrow Mg_3N_2$

Mass of magnesium reacting = (3.26 - x)

Molar mass of Magnesium = 24.3 g/mol

Putting values in equation 1, we get:

Number of moles of magnesium = $\frac{(3.26-x)}{24.3}mol$

By Stoichiometry of the reaction:

3 moles of magnesium produces 1 moles of Mg_3N_2

So, $\frac{(3.26-x)}{24.3}$ moles of magnesium will produce $\frac{1}{3}\times \frac{(3.26-x)}{24.3}=\frac{(3.26-x)}{72.9}$ moles of Mg_3N_2

Molar mass of Mg_3N_2 = 101 g/mol

Putting values in equation 1, we get:

Mass of $Mg_3N_2=\frac{(3.26-x)}{72.9}\times 101=[(3.26-x)\times 1.38]g$

Mass of magnesium nitride = $[(3.26-x)\times 1.38]g$ = Y grams

Calculating the mass of products:

Total mass of the products = 5.09 grams

X+Y=5.09

Putting values of 'X' and 'Y' in above equation, we get:

$(1.66\times x)+[(3.26-x)\times 1.38]=5.09\\\\x=2.11g$

Mass of MgO = $(1.66\times 2.11)=3.502g$

Mass of $Mg_3N_2=[(3.26-2.11)\times 1.38]=1.587g$

Hence, the mass of MgO formed is 3.502 grams and mass of Mg_3N_2 formed is 1.587 grams.

Answer from: Quest

True is ur answer : )

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

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