Galliunm chloride is formed bb the reaction of 2.6 l of a 1.44 m solution of hcl according to the following equation: 2ga +
6hcl ? 2gacl3 + 3h2
(a) outline the steps neccessary to determine the number of moles and mass of h2
(b)perform the calculations outlined

3.8 g H₂

Explanation:

(a)

1. Calculate the moles of HCl that react.

2. Convert the moles of HCl into moles of H₂ using the molar ratio

3. Convert moles of H₂ into mass using the molecular weight (2.02 g/mol)

(b)

1. Calculate the moles of HCl that react.

(1.44mol/L)(2.6L) = 3.744mol HCl

2. Convert the moles of HCl into moles of H₂ using the molar ratio

(3.744mol HCl)(3H₂/6HCl) = 1.872 mol H₂

3. Convert moles of H₂ into mass using the molecular weight (2.02 g/mol)

(1.872 mol H₂)(2.02 g/mol) = 3.8 g H₂

yes it is balanced

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3