the ka of a monoprotic weak acid is 0.00732. what is the percent ionization of a 0.123 m solution of this acid?
percent ionization: %

21.60% is the percent ionization of a 0.123 M solution of this acid.

Explanation:

The equilibrium reaction for dissociation of weak acidis,

initially conc.         c                       0         0

At eqm.                                  

Concentration of the weak acid (c) = 0.123 M

Acid dissociation constant =

Degree of ionization of weak acid =

An expression of dissociation constant is given as:

Percent ionization of weak acid:

a is the answer to this question

explanation: