Determining the empirical and molecular formula for chyrsotile asbestos. chyrsotile has the following percent composition:
28.03% mg, 21.60% si, 1.16% h and 49.21% o. the molar mass of chyrsotile is 520.8 g/mol.

The molecular formula of chyrsotile asbestos :

The empirical formula for chyrsotile asbestos :

Explanation:

The molar mass of chyrsotile = M= 520.8 g/mol.

Let the molecular formula of chyrsotile be

Percentage of Mg = 28.03%

Percentage of Si =21.60%

Percentage of H=1.16%

Percentage of O = 49.21%

Percentage of an element in a compound:

1) Magnesium atom with mass 24 g/mol.

w = 6.0

2) Silicon atom with mass 28 g/mol.

x = 4.0

3) Hydrogen atom with mass 1 g/mol.

y = 6.0

4) Oxygen atom with mass 28 g/mol.

z = 16.0

The molecular formula of chyrsotile asbestos :

Empirical is the lowest ratio of numbers of different atoms present in a compound.

The empirical formula for chyrsotile asbestos :

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current