Achemist adds 0.50l of a 0.485 m copper(ii) sulfate cuso4 solution to a reaction flask. calculate the millimoles of copper(ii) sulfate the chemist has added to the flask. be sure your answer has the correct number of significant digits.

Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

               Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

             Number of millimoles = Molarity × Volume

                                                 = 0.485 M × 500 mL      

                                                 = 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.                                      

the correct answer to this question is 2

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