How many atoms are in the product of the following reaction? 2kclo3 ⇋ 2kcl + 3o2 6 8 5 10

10 is the answer.

Explanation:

Balancing is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient × subscript  

For example   contains  

5 × 1 = 5 , Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms  (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So 3 × 3 = 9, Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

Product side contains

2, K  

2, Cl

6, O  

So totally 2 + 2 + 6 = 10 atoms present on the product side

for points guys

the answer is 303.15 or 303