How many grams of n are in 82.0g of nh2no3?

29.44 grams

Explanation:

Molar Mass of NH2NO3 = Molar Mass of Nitrogen + 2(Molar Mass of Hydrogen) + Molar Mass of Nitrogen + 3(Molar Mass of Oxygen)

Molar Mass of NH2NO3 = 14 + 2(1) + 14 + 3(16) = 78 grams

Mass of Nitrogen in NH2NO3 = 14 + 14 = 28 grams

Percentage by mass of Nitrogen in NH2NO3 =

This means, the percentage of Nitrogen in NH2NO3 is 35.90%. So the amount of Nitrogen in 82 g of NH2NO3 will be 35.90% of 82

35.90% of 82 = 0.359 x 82 = 29.44 grams.

Thus, 29.44 grams of Nitrogen will be present in 82 grams of NH2NO3

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

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