If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 k, and then the pressure is raised to 15 atm and the temperature is raised to 302 k, what will be the resulting volume of the gas

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

Solving for V₂ , we get:

V₂ = 15.04 mL

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explanation: